Handjob question

dmnEPC

dmnEPC

New member
Dec 23, 2010
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I was at an election party last week. everyone gave a handjob with everybody else. There were 66 handjobs. How many people went to the handjob party?
 


"With" implies mutual handjobs, as is to be expected at such events, i.e., you jack me off while i jack you off. We jack each other off. Sometimes together, sometimes serially.

So...if there were a total of 66 handjobs given, then there were 33 people at the party. AMIRITE?
 
vikingred said:
"With" implies mutual handjobs, as is to be expected at such events, i.e., you jack me off while i jack you off. We jack each other off. Sometimes together, sometimes serially.

So...if there were a total of 66 handjobs given, then there were 33 people at the party. AMIRITE?
Click to expand...

Sorry. You must be American? Amirite?
 
sum over i where i e {0, .., n}. solve for n

66 = n(n-1)/2, solve that
 
if (electionparty === handjobparty) {
echo "66";
}
else echo "I see what you did there";
 
This is for the OP:

hairy-stomach-face-circle-of-hell-550x385.jpg


And yeah, I'm American. U Mad?
 
if we are talking circlejerk then i believe 66 would be correct? Meaning if there were 66 handjobs and everyone was giving while receiving, that would be 66 given handjobs and 66 received handjobs. However now I wonder if that is 132 handjobs as one may count a recieved one as a handjobs AND a given one as a handjob. Hmmm... my handjob math isn't what it used to be.
 
dewoof01 said:
if we are talking circlejerk then i believe 66 would be correct? Meaning if there were 66 handjobs and everyone was giving while receiving, that would be 66 given handjobs and 66 received handjobs. However now I wonder if that is 132 handjobs as one may count a recieved one as a handjobs AND a given one as a handjob. Hmmm... my handjob math isn't what it used to be.
Click to expand...

Who did you buy this account from, Fuckface?
 
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